Header

  1. View current page

    수학이 알고싶은 중고대딩들을 위한 수학 노트

코쉬 행렬과 행렬식

이 항목의 스프링노트 원문주소

 

 

개요

a_{ij}={\frac{1}{x_i-y_j}}

\left( \begin{array}{c} \frac{1}{x_1-y_1} \end{array} \right)

\left( \begin{array}{cc} \frac{1}{x_1-y_1} & \frac{1}{x_1-y_2} \ \frac{1}{x_2-y_1} & \frac{1}{x_2-y_2} \end{array} \right)

 

n=3인 경우

\left( \begin{array}{ccc} \frac{1}{x_1-y_1} & \frac{1}{x_1-y_2} & \frac{1}{x_1-y_3} \ \frac{1}{x_2-y_1} & \frac{1}{x_2-y_2} & \frac{1}{x_2-y_3} \ \frac{1}{x_3-y_1} & \frac{1}{x_3-y_2} & \frac{1}{x_3-y_3} \end{array} \right)

행렬식은

-\frac{\left(-x_1+x_2\right) \left(-x_1+x_3\right) \left(-x_2+x_3\right) \left(y_1-y_2\right) \left(y_1-y_3\right) \left(y_2-y_3\right)}{\left(x_3-y_1\right) \left(-x_1+y_1\right) \left(-x_2+y_1\right) \left(x_2-y_2\right) \left(x_3-y_2\right) \left(-x_1+y_2\right) \left(x_1-y_3\right) \left(x_2-y_3\right) \left(x_3-y_3\right)}

 

n=4인 경우

\left( \begin{array}{cccc} \frac{1}{x_1-y_1} & \frac{1}{x_1-y_2} & \frac{1}{x_1-y_3} & \frac{1}{x_1-y_4} \ \frac{1}{x_2-y_1} & \frac{1}{x_2-y_2} & \frac{1}{x_2-y_3} & \frac{1}{x_2-y_4} \ \frac{1}{x_3-y_1} & \frac{1}{x_3-y_2} & \frac{1}{x_3-y_3} & \frac{1}{x_3-y_4} \ \frac{1}{x_4-y_1} & \frac{1}{x_4-y_2} & \frac{1}{x_4-y_3} & \frac{1}{x_4-y_4} \end{array} \right)

 

 

역사

 

 

 

메모

 

 

관련된 항목들

 

 

수학용어번역

 

 

매스매티카 파일 및 계산 리소스

 

 

 

사전 형태의 자료

 

 

 

 

관련논문

 

 

관련도서
  • 도서내검색

    • http://books.google.com/books?q=
    • http://book.daum.net/search/contentSearch.do?query=
  • 도서검색

    • http://books.google.com/books?q=
    • http://book.daum.net/search/mainSearch.do?query=
    • http://book.daum.net/search/mainSearch.do?query=

 

 

관련기사
  • 네이버 뉴스 검색 (키워드 수정)

    • http://news.search.naver.com/search.naver?where=news&x=0&y=0&sm=tab_hty&query=
    • http://news.search.naver.com/search.naver?where=news&x=0&y=0&sm=tab_hty&query=
    • http://news.search.naver.com/search.naver?where=news&x=0&y=0&sm=tab_hty&query=

 

 

블로그

History

Last edited on 12/09/2011 14:02 by 피타고라스

Comments (0)

You must log in to leave a comment. Please sign in.